2(-2x-3)=3(-x+2)

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Solution for 2(-2x-3)=3(-x+2) equation:



2(-2x-3)=3(-x+2)
We move all terms to the left:
2(-2x-3)-(3(-x+2))=0
We add all the numbers together, and all the variables
2(-2x-3)-(3(-1x+2))=0
We multiply parentheses
-4x-(3(-1x+2))-6=0
We calculate terms in parentheses: -(3(-1x+2)), so:
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
We get rid of parentheses
-4x+3x-6-6=0
We add all the numbers together, and all the variables
-1x-12=0
We move all terms containing x to the left, all other terms to the right
-x=12
x=12/-1
x=-12

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