2(-2z-2)=3(-2z+6)

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Solution for 2(-2z-2)=3(-2z+6) equation: 



2(-2z-2)=3(-2z+6)

We move all terms to the left:

2(-2z-2)-(3(-2z+6))=0

We multiply parentheses

-4z-(3(-2z+6))-4=0



We calculate terms in parentheses: -(3(-2z+6)), so:

3(-2z+6)

We multiply parentheses

-6z+18

Back to the equation:

-(-6z+18)



We get rid of parentheses

-4z+6z-18-4=0

We add all the numbers together, and all the variables

2z-22=0

We move all terms containing z to the left, all other terms to the right

2z=22

z=22/2

z=11

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