2(-3+3x)=34(2x+1)

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Solution for 2(-3+3x)=34(2x+1) equation: 



2(-3+3x)=34(2x+1)

We move all terms to the left:

2(-3+3x)-(34(2x+1))=0

We add all the numbers together, and all the variables

2(3x-3)-(34(2x+1))=0

We multiply parentheses

6x-(34(2x+1))-6=0



We calculate terms in parentheses: -(34(2x+1)), so:

34(2x+1)

We multiply parentheses

68x+34

Back to the equation:

-(68x+34)



We get rid of parentheses

6x-68x-34-6=0

We add all the numbers together, and all the variables

-62x-40=0

We move all terms containing x to the left, all other terms to the right

-62x=40

x=40/-62

x=-20/31

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