2(-3-b)-2b=6(-b+2)-26

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Solution for 2(-3-b)-2b=6(-b+2)-26 equation: 



2(-3-b)-2b=6(-b+2)-26

We move all terms to the left:

2(-3-b)-2b-(6(-b+2)-26)=0

We add all the numbers together, and all the variables

2(-1b-3)-2b-(6(-1b+2)-26)=0

We add all the numbers together, and all the variables

-2b+2(-1b-3)-(6(-1b+2)-26)=0

We multiply parentheses

-2b-2b-(6(-1b+2)-26)-6=0



We calculate terms in parentheses: -(6(-1b+2)-26), so:

6(-1b+2)-26

We multiply parentheses

-6b+12-26

We add all the numbers together, and all the variables

-6b-14

Back to the equation:

-(-6b-14)



We add all the numbers together, and all the variables

-4b-(-6b-14)-6=0

We get rid of parentheses

-4b+6b+14-6=0

We add all the numbers together, and all the variables

2b+8=0

We move all terms containing b to the left, all other terms to the right

2b=-8

b=-8/2

b=-4

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