2(-3a+5)=-4a(a+4)

Solution for 2(-3a+5)=-4a(a+4) equation:

2(-3a+5)=-4a(a+4)

We move all terms to the left:

2(-3a+5)-(-4a(a+4))=0

We multiply parentheses

-6a-(-4a(a+4))+10=0


We calculate terms in parentheses: -(-4a(a+4)), so:

-4a(a+4)

We multiply parentheses

-4a^2-16a

Back to the equation:

-(-4a^2-16a)


We get rid of parentheses

4a^2+16a-6a+10=0

We add all the numbers together, and all the variables

4a^2+10a+10=0

a = 4; b = 10; c = +10;
Δ = b2-4ac
Δ = 102-4·4·10
Δ = -60
Delta is less than zero, so there is no solution for the equation