2(-41/2+m)+3=4(m-3)=51/2

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Solution for 2(-41/2+m)+3=4(m-3)=51/2 equation: 



2(-41/2+m)+3=4(m-3)=51/2

We move all terms to the left:

2(-41/2+m)+3-(4(m-3))=0



Domain of the equation: 2+m)!=0

We move all terms containing m to the left, all other terms to the right

m)!=-2

m!=-2/1

m!=-2

m∈R



We add all the numbers together, and all the variables

2(+m-41/2)-(4(m-3))+3=0

We multiply parentheses

2m-(4(m-3))+3-41/2*2=0

We multiply all the terms by the denominator


2m*2*2-((4(m-3)))*2*2-41+3*2*2=0

We add all the numbers together, and all the variables

2m*2*2-((4(m-3)))*2*2-29=0

Wy multiply elements

8m*2-((4(m-3)))*2*2-29=0

Wy multiply elements

16m-((4(m-3)))*2*2-29=0

We move all terms containing m to the left, all other terms to the right

16m-((4(m-3)))*2*2=29

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