2(-4b-8)+26=5(-7b-11)+11

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Solution for 2(-4b-8)+26=5(-7b-11)+11 equation: 



2(-4b-8)+26=5(-7b-11)+11

We move all terms to the left:

2(-4b-8)+26-(5(-7b-11)+11)=0

We multiply parentheses

-8b-(5(-7b-11)+11)-16+26=0



We calculate terms in parentheses: -(5(-7b-11)+11), so:

5(-7b-11)+11

We multiply parentheses

-35b-55+11

We add all the numbers together, and all the variables

-35b-44

Back to the equation:

-(-35b-44)



We add all the numbers together, and all the variables

-8b-(-35b-44)+10=0

We get rid of parentheses

-8b+35b+44+10=0

We add all the numbers together, and all the variables

27b+54=0

We move all terms containing b to the left, all other terms to the right

27b=-54

b=-54/27

b=-2

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