2(-6+11)-42=10(-b-2)-8

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Solution for 2(-6+11)-42=10(-b-2)-8 equation: 



2(-6+11)-42=10(-b-2)-8

We move all terms to the left:

2(-6+11)-42-(10(-b-2)-8)=0

We add all the numbers together, and all the variables

-(10(-1b-2)-8)-42+25=0

We add all the numbers together, and all the variables

-(10(-1b-2)-8)-17=0



We calculate terms in parentheses: -(10(-1b-2)-8), so:

10(-1b-2)-8

We multiply parentheses

-10b-20-8

We add all the numbers together, and all the variables

-10b-28

Back to the equation:

-(-10b-28)



We get rid of parentheses

10b+28-17=0

We add all the numbers together, and all the variables

10b+11=0

We move all terms containing b to the left, all other terms to the right

10b=-11

b=-11/10

b=-1+1/10

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