2(-6b+11)-42=10(-b-2)-8

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Solution for 2(-6b+11)-42=10(-b-2)-8 equation: 



2(-6b+11)-42=10(-b-2)-8

We move all terms to the left:

2(-6b+11)-42-(10(-b-2)-8)=0

We add all the numbers together, and all the variables

2(-6b+11)-(10(-1b-2)-8)-42=0

We multiply parentheses

-12b-(10(-1b-2)-8)+22-42=0



We calculate terms in parentheses: -(10(-1b-2)-8), so:

10(-1b-2)-8

We multiply parentheses

-10b-20-8

We add all the numbers together, and all the variables

-10b-28

Back to the equation:

-(-10b-28)



We add all the numbers together, and all the variables

-12b-(-10b-28)-20=0

We get rid of parentheses

-12b+10b+28-20=0

We add all the numbers together, and all the variables

-2b+8=0

We move all terms containing b to the left, all other terms to the right

-2b=-8

b=-8/-2

b=+4

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