2(-6c-3)=3c+7

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Solution for 2(-6c-3)=3c+7 equation: 



2(-6c-3)=3c+7

We move all terms to the left:

2(-6c-3)-(3c+7)=0

We multiply parentheses

-12c-(3c+7)-6=0

We get rid of parentheses

-12c-3c-7-6=0

We add all the numbers together, and all the variables

-15c-13=0

We move all terms containing c to the left, all other terms to the right

-15c=13

c=13/-15

c=-13/15

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