2(-6r-2r+3)=8r+42

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Solution for 2(-6r-2r+3)=8r+42 equation: 



2(-6r-2r+3)=8r+42

We move all terms to the left:

2(-6r-2r+3)-(8r+42)=0

We add all the numbers together, and all the variables

2(-8r+3)-(8r+42)=0

We multiply parentheses

-16r-(8r+42)+6=0

We get rid of parentheses

-16r-8r-42+6=0

We add all the numbers together, and all the variables

-24r-36=0

We move all terms containing r to the left, all other terms to the right

-24r=36

r=36/-24

r=-1+1/2

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