2(-6y+68)=(y+5)+(2y+11)

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Solution for 2(-6y+68)=(y+5)+(2y+11) equation: 



2(-6y+68)=(y+5)+(2y+11)

We move all terms to the left:

2(-6y+68)-((y+5)+(2y+11))=0

We multiply parentheses

-12y-((y+5)+(2y+11))+136=0



We calculate terms in parentheses: -((y+5)+(2y+11)), so:

(y+5)+(2y+11)

We get rid of parentheses

y+2y+5+11

We add all the numbers together, and all the variables

3y+16

Back to the equation:

-(3y+16)



We get rid of parentheses

-12y-3y-16+136=0

We add all the numbers together, and all the variables

-15y+120=0

We move all terms containing y to the left, all other terms to the right

-15y=-120

y=-120/-15

y=+8

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