2(-7-a)+8(a+4)=7+8a-1

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Solution for 2(-7-a)+8(a+4)=7+8a-1 equation: 



2(-7-a)+8(a+4)=7+8a-1

We move all terms to the left:

2(-7-a)+8(a+4)-(7+8a-1)=0

We add all the numbers together, and all the variables

2(-1a-7)+8(a+4)-(8a+6)=0

We multiply parentheses

-2a+8a-(8a+6)-14+32=0

We get rid of parentheses

-2a+8a-8a-6-14+32=0

We add all the numbers together, and all the variables

-2a+12=0

We move all terms containing a to the left, all other terms to the right

-2a=-12

a=-12/-2

a=+6

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