2(-7z+28)=4z-34+z

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Solution for 2(-7z+28)=4z-34+z equation: 



2(-7z+28)=4z-34+z

We move all terms to the left:

2(-7z+28)-(4z-34+z)=0

We add all the numbers together, and all the variables

2(-7z+28)-(5z-34)=0

We multiply parentheses

-14z-(5z-34)+56=0

We get rid of parentheses

-14z-5z+34+56=0

We add all the numbers together, and all the variables

-19z+90=0

We move all terms containing z to the left, all other terms to the right

-19z=-90

z=-90/-19

z=4+14/19

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