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2(-90+x+x2)=0
We add all the numbers together, and all the variables
2(+x+x^2-90)=0
We multiply parentheses
2x^2+2x-180=0
a = 2; b = 2; c = -180;
Δ = b2-4ac
Δ = 22-4·2·(-180)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*2}=\frac{-40}{4} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*2}=\frac{36}{4} =9 $
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