2(-a-8)=10(-a+3)

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Solution for 2(-a-8)=10(-a+3) equation: 



2(-a-8)=10(-a+3)

We move all terms to the left:

2(-a-8)-(10(-a+3))=0

We add all the numbers together, and all the variables

2(-1a-8)-(10(-1a+3))=0

We multiply parentheses

-2a-(10(-1a+3))-16=0



We calculate terms in parentheses: -(10(-1a+3)), so:

10(-1a+3)

We multiply parentheses

-10a+30

Back to the equation:

-(-10a+30)



We get rid of parentheses

-2a+10a-30-16=0

We add all the numbers together, and all the variables

8a-46=0

We move all terms containing a to the left, all other terms to the right

8a=46

a=46/8

a=5+3/4

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