2(-x+1)+5x=7(x+1)+4x

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Solution for 2(-x+1)+5x=7(x+1)+4x equation: 



2(-x+1)+5x=7(x+1)+4x

We move all terms to the left:

2(-x+1)+5x-(7(x+1)+4x)=0

We add all the numbers together, and all the variables

2(-1x+1)+5x-(7(x+1)+4x)=0

We add all the numbers together, and all the variables

5x+2(-1x+1)-(7(x+1)+4x)=0

We multiply parentheses

5x-2x-(7(x+1)+4x)+2=0



We calculate terms in parentheses: -(7(x+1)+4x), so:

7(x+1)+4x

We add all the numbers together, and all the variables

4x+7(x+1)

We multiply parentheses

4x+7x+7

We add all the numbers together, and all the variables

11x+7

Back to the equation:

-(11x+7)



We add all the numbers together, and all the variables

3x-(11x+7)+2=0

We get rid of parentheses

3x-11x-7+2=0

We add all the numbers together, and all the variables

-8x-5=0

We move all terms containing x to the left, all other terms to the right

-8x=5

x=5/-8

x=-5/8

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