2(-x+3x)+3(-x)+7=(-x)+-3x(-3)

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Solution for 2(-x+3x)+3(-x)+7=(-x)+-3x(-3) equation: 



2(-x+3x)+3(-x)+7=(-x)+-3x(-3)

We move all terms to the left:

2(-x+3x)+3(-x)+7-((-x)+-3x(-3))=0

We add all the numbers together, and all the variables

2(+2x)+3(-1x)-((-1x)+-3x(-3))+7=0

We use the square of the difference formula

2(+2x)+3(-1x)-((-1x)-3x(-3))+7=0

We multiply parentheses

4x-3x-((-1x)-3x(-3))+7=0



We calculate terms in parentheses: -((-1x)-3x(-3)), so:

(-1x)-3x(-3)

We multiply parentheses

(-1x)+9x

We get rid of parentheses

-1x+9x

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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