2(-x-2)-3(x-4)=-2(x+2)-5

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Solution for 2(-x-2)-3(x-4)=-2(x+2)-5 equation: 



2(-x-2)-3(x-4)=-2(x+2)-5

We move all terms to the left:

2(-x-2)-3(x-4)-(-2(x+2)-5)=0

We add all the numbers together, and all the variables

2(-1x-2)-3(x-4)-(-2(x+2)-5)=0

We multiply parentheses

-2x-3x-(-2(x+2)-5)-4+12=0



We calculate terms in parentheses: -(-2(x+2)-5), so:

-2(x+2)-5

We multiply parentheses

-2x-4-5

We add all the numbers together, and all the variables

-2x-9

Back to the equation:

-(-2x-9)



We add all the numbers together, and all the variables

-5x-(-2x-9)+8=0

We get rid of parentheses

-5x+2x+9+8=0

We add all the numbers together, and all the variables

-3x+17=0

We move all terms containing x to the left, all other terms to the right

-3x=-17

x=-17/-3

x=5+2/3

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