2(-z+2)+2z=4

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Solution for 2(-z+2)+2z=4 equation: 



2(-z+2)+2z=4

We move all terms to the left:

2(-z+2)+2z-(4)=0

We add all the numbers together, and all the variables

2(-1z+2)+2z-4=0

We add all the numbers together, and all the variables

2z+2(-1z+2)-4=0

We multiply parentheses

2z-2z+4-4=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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