2(0+x)(12+x)=128

Solution for 2(0+x)(12+x)=128 equation:

Simplifying
2(0 + x)(12 + x) = 128
Remove the zero:
2(x)(12 + x) = 128
(12 * 2x + x * 2x) = 128
(24x + 2x2) = 128

Solving
24x + 2x2 = 128

Solving for variable 'x'.

Reorder the terms:
-128 + 24x + 2x2 = 128 + -128

Combine like terms: 128 + -128 = 0
-128 + 24x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-64 + 12x + x2) = 0

Factor a trinomial.
2((-16 + -1x)(4 + -1x)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-16 + -1x)' equal to zero and attempt to solve:

Simplifying
-16 + -1x = 0

Solving
-16 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -1x = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -1x = 0 + 16
-1x = 0 + 16

Combine like terms: 0 + 16 = 16
-1x = 16

Divide each side by '-1'.
x = -16

Simplifying
x = -16
Subproblem 2
Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying
4 + -1x = 0

Solving
4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1x = 0 + -4
-1x = 0 + -4

Combine like terms: 0 + -4 = -4
-1x = -4

Divide each side by '-1'.
x = 4

Simplifying
x = 4
Solution
x = {-16, 4}