2(0x-2)+10=6x+42

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Solution for 2(0x-2)+10=6x+42 equation: 



2(0x-2)+10=6x+42

We move all terms to the left:

2(0x-2)+10-(6x+42)=0

We add all the numbers together, and all the variables

2(x-2)-(6x+42)+10=0

We multiply parentheses

2x-(6x+42)-4+10=0

We get rid of parentheses

2x-6x-42-4+10=0

We add all the numbers together, and all the variables

-4x-36=0

We move all terms containing x to the left, all other terms to the right

-4x=36

x=36/-4

x=-9

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