2(1)(3)(m-1+12(b))=18

Solution for 2(1)(3)(m-1+12(b))=18 equation:

Simplifying
2(1)(3)(m + -1 + 12(b)) = 18

Reorder the terms:
2 * 1 * 3(-1 + 12b + m) = 18

Multiply 2 * 1
2 * 3(-1 + 12b + m) = 18

Multiply 2 * 3
6(-1 + 12b + m) = 18
(-1 * 6 + 12b * 6 + m * 6) = 18
(-6 + 72b + 6m) = 18

Solving
-6 + 72b + 6m = 18

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 72b + 6 + 6m = 18 + 6

Reorder the terms:
-6 + 6 + 72b + 6m = 18 + 6

Combine like terms: -6 + 6 = 0
0 + 72b + 6m = 18 + 6
72b + 6m = 18 + 6

Combine like terms: 18 + 6 = 24
72b + 6m = 24

Add '-6m' to each side of the equation.
72b + 6m + -6m = 24 + -6m

Combine like terms: 6m + -6m = 0
72b + 0 = 24 + -6m
72b = 24 + -6m

Divide each side by '72'.
b = 0.3333333333 + -0.08333333333m

Simplifying
b = 0.3333333333 + -0.08333333333m