2(1+2b)+6(b+5)=b-8+1+6b

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Solution for 2(1+2b)+6(b+5)=b-8+1+6b equation: 



2(1+2b)+6(b+5)=b-8+1+6b

We move all terms to the left:

2(1+2b)+6(b+5)-(b-8+1+6b)=0

We add all the numbers together, and all the variables

2(2b+1)+6(b+5)-(7b-7)=0

We multiply parentheses

4b+6b-(7b-7)+2+30=0

We get rid of parentheses

4b+6b-7b+7+2+30=0

We add all the numbers together, and all the variables

3b+39=0

We move all terms containing b to the left, all other terms to the right

3b=-39

b=-39/3

b=-13

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