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2(1+2x)=2(-2x+14)/2
We move all terms to the left:
2(1+2x)-(2(-2x+14)/2)=0
We add all the numbers together, and all the variables
2(2x+1)-(2(-2x+14)/2)=0
We multiply parentheses
4x-(2(-2x+14)/2)+2=0
We multiply all the terms by the denominator
4x*2)-(2(-2x+14)+2*2)=0
We add all the numbers together, and all the variables
4x*2)-(2(-2x+14)=0
Wy multiply elements
8x^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{16}=0$
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