2(1+3k)+6=16+2k

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Solution for 2(1+3k)+6=16+2k equation:



2(1+3k)+6=16+2k
We move all terms to the left:
2(1+3k)+6-(16+2k)=0
We add all the numbers together, and all the variables
2(3k+1)-(2k+16)+6=0
We multiply parentheses
6k-(2k+16)+2+6=0
We get rid of parentheses
6k-2k-16+2+6=0
We add all the numbers together, and all the variables
4k-8=0
We move all terms containing k to the left, all other terms to the right
4k=8
k=8/4
k=2

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