2(1+3x)=16-x

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Solution for 2(1+3x)=16-x equation: 



2(1+3x)=16-x

We move all terms to the left:

2(1+3x)-(16-x)=0

We add all the numbers together, and all the variables

2(3x+1)-(-1x+16)=0

We multiply parentheses

6x-(-1x+16)+2=0

We get rid of parentheses

6x+1x-16+2=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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