2(1+3y)=12-4y

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Solution for 2(1+3y)=12-4y equation: 



2(1+3y)=12-4y

We move all terms to the left:

2(1+3y)-(12-4y)=0

We add all the numbers together, and all the variables

2(3y+1)-(-4y+12)=0

We multiply parentheses

6y-(-4y+12)+2=0

We get rid of parentheses

6y+4y-12+2=0

We add all the numbers together, and all the variables

10y-10=0

We move all terms containing y to the left, all other terms to the right

10y=10

y=10/10

y=1

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