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2(1+4a)-3a=1+3(3+5a)
We move all terms to the left:
2(1+4a)-3a-(1+3(3+5a))=0
We add all the numbers together, and all the variables
2(4a+1)-3a-(1+3(5a+3))=0
We add all the numbers together, and all the variables
-3a+2(4a+1)-(1+3(5a+3))=0
We multiply parentheses
-3a+8a-(1+3(5a+3))+2=0
We calculate terms in parentheses: -(1+3(5a+3)), so:We add all the numbers together, and all the variables
1+3(5a+3)
determiningTheFunctionDomain 3(5a+3)+1
We multiply parentheses
15a+9+1
We add all the numbers together, and all the variables
15a+10
Back to the equation:
-(15a+10)
5a-(15a+10)+2=0
We get rid of parentheses
5a-15a-10+2=0
We add all the numbers together, and all the variables
-10a-8=0
We move all terms containing a to the left, all other terms to the right
-10a=8
a=8/-10
a=-4/5
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