2(1+4x)=6(2x+5)

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Solution for 2(1+4x)=6(2x+5) equation: 



2(1+4x)=6(2x+5)

We move all terms to the left:

2(1+4x)-(6(2x+5))=0

We add all the numbers together, and all the variables

2(4x+1)-(6(2x+5))=0

We multiply parentheses

8x-(6(2x+5))+2=0



We calculate terms in parentheses: -(6(2x+5)), so:

6(2x+5)

We multiply parentheses

12x+30

Back to the equation:

-(12x+30)



We get rid of parentheses

8x-12x-30+2=0

We add all the numbers together, and all the variables

-4x-28=0

We move all terms containing x to the left, all other terms to the right

-4x=28

x=28/-4

x=-7

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