2(1+6r)=2r+32

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Solution for 2(1+6r)=2r+32 equation: 



2(1+6r)=2r+32

We move all terms to the left:

2(1+6r)-(2r+32)=0

We add all the numbers together, and all the variables

2(6r+1)-(2r+32)=0

We multiply parentheses

12r-(2r+32)+2=0

We get rid of parentheses

12r-2r-32+2=0

We add all the numbers together, and all the variables

10r-30=0

We move all terms containing r to the left, all other terms to the right

10r=30

r=30/10

r=3

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