2(1+m)+15=4m+3m+12

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Solution for 2(1+m)+15=4m+3m+12 equation: 



2(1+m)+15=4m+3m+12

We move all terms to the left:

2(1+m)+15-(4m+3m+12)=0

We add all the numbers together, and all the variables

2(m+1)-(7m+12)+15=0

We multiply parentheses

2m-(7m+12)+2+15=0

We get rid of parentheses

2m-7m-12+2+15=0

We add all the numbers together, and all the variables

-5m+5=0

We move all terms containing m to the left, all other terms to the right

-5m=-5

m=-5/-5

m=1

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