2(1+x)=2(3x+19)

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Solution for 2(1+x)=2(3x+19) equation: 



2(1+x)=2(3x+19)

We move all terms to the left:

2(1+x)-(2(3x+19))=0

We add all the numbers together, and all the variables

2(x+1)-(2(3x+19))=0

We multiply parentheses

2x-(2(3x+19))+2=0



We calculate terms in parentheses: -(2(3x+19)), so:

2(3x+19)

We multiply parentheses

6x+38

Back to the equation:

-(6x+38)



We get rid of parentheses

2x-6x-38+2=0

We add all the numbers together, and all the variables

-4x-36=0

We move all terms containing x to the left, all other terms to the right

-4x=36

x=36/-4

x=-9

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