2(1+x)=2+3(x-2)

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Solution for 2(1+x)=2+3(x-2) equation: 



2(1+x)=2+3(x-2)

We move all terms to the left:

2(1+x)-(2+3(x-2))=0

We add all the numbers together, and all the variables

2(x+1)-(2+3(x-2))=0

We multiply parentheses

2x-(2+3(x-2))+2=0



We calculate terms in parentheses: -(2+3(x-2)), so:

2+3(x-2)

determiningTheFunctionDomain
3(x-2)+2

We multiply parentheses

3x-6+2

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We get rid of parentheses

2x-3x+4+2=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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