2(1-3x)-3(x+2)=-5(x-4)

Solution for 2(1-3x)-3(x+2)=-5(x-4) equation:

2(1-3x)-3(x+2)=-5(x-4)

We move all terms to the left:

2(1-3x)-3(x+2)-(-5(x-4))=0

We add all the numbers together, and all the variables

2(-3x+1)-3(x+2)-(-5(x-4))=0

We multiply parentheses

-6x-3x-(-5(x-4))+2-6=0


We calculate terms in parentheses: -(-5(x-4)), so:

-5(x-4)

We multiply parentheses

-5x+20

Back to the equation:

-(-5x+20)


We add all the numbers together, and all the variables

-9x-(-5x+20)-4=0

We get rid of parentheses

-9x+5x-20-4=0

We add all the numbers together, and all the variables

-4x-24=0

We move all terms containing x to the left, all other terms to the right

-4x=24

x=24/-4

x=-6