2(1-4b)=4+2(8b-1)

Solution for 2(1-4b)=4+2(8b-1) equation:

2(1-4b)=4+2(8b-1)

We move all terms to the left:

2(1-4b)-(4+2(8b-1))=0

We add all the numbers together, and all the variables

2(-4b+1)-(4+2(8b-1))=0

We multiply parentheses

-8b-(4+2(8b-1))+2=0


We calculate terms in parentheses: -(4+2(8b-1)), so:

4+2(8b-1)

determiningTheFunctionDomain
2(8b-1)+4

We multiply parentheses

16b-2+4

We add all the numbers together, and all the variables

16b+2

Back to the equation:

-(16b+2)


We get rid of parentheses

-8b-16b-2+2=0

We add all the numbers together, and all the variables

-24b=0

b=0/-24

b=0