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2(1-4x)=(-1/2x)
We move all terms to the left:
2(1-4x)-((-1/2x))=0
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(-4x+1)-((-1/2x))=0
We multiply parentheses
-8x-((-1/2x))+2=0
We multiply all the terms by the denominator
-8x*2x))-((+2*2x))-1=0
Wy multiply elements
-16x^2+4x=0
a = -16; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-16)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-16}=\frac{-8}{-32} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-16}=\frac{0}{-32} =0 $
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