2(1-5y)+3(6+7y)=42

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Solution for 2(1-5y)+3(6+7y)=42 equation: 



2(1-5y)+3(6+7y)=42

We move all terms to the left:

2(1-5y)+3(6+7y)-(42)=0

We add all the numbers together, and all the variables

2(-5y+1)+3(7y+6)-42=0

We multiply parentheses

-10y+21y+2+18-42=0

We add all the numbers together, and all the variables

11y-22=0

We move all terms containing y to the left, all other terms to the right

11y=22

y=22/11

y=2

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