2(1-6x)=-(7x-5)+7

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Solution for 2(1-6x)=-(7x-5)+7 equation: 



2(1-6x)=-(7x-5)+7

We move all terms to the left:

2(1-6x)-(-(7x-5)+7)=0

We add all the numbers together, and all the variables

2(-6x+1)-(-(7x-5)+7)=0

We multiply parentheses

-12x-(-(7x-5)+7)+2=0



We calculate terms in parentheses: -(-(7x-5)+7), so:

-(7x-5)+7

We get rid of parentheses

-7x+5+7

We add all the numbers together, and all the variables

-7x+12

Back to the equation:

-(-7x+12)



We get rid of parentheses

-12x+7x-12+2=0

We add all the numbers together, and all the variables

-5x-10=0

We move all terms containing x to the left, all other terms to the right

-5x=10

x=10/-5

x=-2

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