2(1-6x)=-4(3x+2)+10

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Solution for 2(1-6x)=-4(3x+2)+10 equation:



2(1-6x)=-4(3x+2)+10
We move all terms to the left:
2(1-6x)-(-4(3x+2)+10)=0
We add all the numbers together, and all the variables
2(-6x+1)-(-4(3x+2)+10)=0
We multiply parentheses
-12x-(-4(3x+2)+10)+2=0
We calculate terms in parentheses: -(-4(3x+2)+10), so:
-4(3x+2)+10
We multiply parentheses
-12x-8+10
We add all the numbers together, and all the variables
-12x+2
Back to the equation:
-(-12x+2)
We get rid of parentheses
-12x+12x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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