2(1-6x)=-4(3x+2)+10

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Solution for 2(1-6x)=-4(3x+2)+10 equation: 



2(1-6x)=-4(3x+2)+10

We move all terms to the left:

2(1-6x)-(-4(3x+2)+10)=0

We add all the numbers together, and all the variables

2(-6x+1)-(-4(3x+2)+10)=0

We multiply parentheses

-12x-(-4(3x+2)+10)+2=0



We calculate terms in parentheses: -(-4(3x+2)+10), so:

-4(3x+2)+10

We multiply parentheses

-12x-8+10

We add all the numbers together, and all the variables

-12x+2

Back to the equation:

-(-12x+2)



We get rid of parentheses

-12x+12x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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