2(1-x)-3=3(2x+1)+2

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Solution for 2(1-x)-3=3(2x+1)+2 equation: 



2(1-x)-3=3(2x+1)+2

We move all terms to the left:

2(1-x)-3-(3(2x+1)+2)=0

We add all the numbers together, and all the variables

2(-1x+1)-(3(2x+1)+2)-3=0

We multiply parentheses

-2x-(3(2x+1)+2)+2-3=0



We calculate terms in parentheses: -(3(2x+1)+2), so:

3(2x+1)+2

We multiply parentheses

6x+3+2

We add all the numbers together, and all the variables

6x+5

Back to the equation:

-(6x+5)



We add all the numbers together, and all the variables

-2x-(6x+5)-1=0

We get rid of parentheses

-2x-6x-5-1=0

We add all the numbers together, and all the variables

-8x-6=0

We move all terms containing x to the left, all other terms to the right

-8x=6

x=6/-8

x=-3/4

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