2(1-x)-x+2=-6(2+x)

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Solution for 2(1-x)-x+2=-6(2+x) equation: 



2(1-x)-x+2=-6(2+x)

We move all terms to the left:

2(1-x)-x+2-(-6(2+x))=0

We add all the numbers together, and all the variables

2(-1x+1)-x-(-6(x+2))+2=0

We add all the numbers together, and all the variables

-1x+2(-1x+1)-(-6(x+2))+2=0

We multiply parentheses

-1x-2x-(-6(x+2))+2+2=0



We calculate terms in parentheses: -(-6(x+2)), so:

-6(x+2)

We multiply parentheses

-6x-12

Back to the equation:

-(-6x-12)



We add all the numbers together, and all the variables

-3x-(-6x-12)+4=0

We get rid of parentheses

-3x+6x+12+4=0

We add all the numbers together, and all the variables

3x+16=0

We move all terms containing x to the left, all other terms to the right

3x=-16

x=-16/3

x=-5+1/3

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