2(1-z)-2=2(2z+3)

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Solution for 2(1-z)-2=2(2z+3) equation: 



2(1-z)-2=2(2z+3)

We move all terms to the left:

2(1-z)-2-(2(2z+3))=0

We add all the numbers together, and all the variables

2(-1z+1)-(2(2z+3))-2=0

We multiply parentheses

-2z-(2(2z+3))+2-2=0



We calculate terms in parentheses: -(2(2z+3)), so:

2(2z+3)

We multiply parentheses

4z+6

Back to the equation:

-(4z+6)



We add all the numbers together, and all the variables

-2z-(4z+6)=0

We get rid of parentheses

-2z-4z-6=0

We add all the numbers together, and all the variables

-6z-6=0

We move all terms containing z to the left, all other terms to the right

-6z=6

z=6/-6

z=-1

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