2(1.3t+2)+1.2=2(t+1)+0.6t

Solution for 2(1.3t+2)+1.2=2(t+1)+0.6t equation:

2(1.3t+2)+1.2=2(t+1)+0.6t

We move all terms to the left:

2(1.3t+2)+1.2-(2(t+1)+0.6t)=0

We multiply parentheses

2t-(2(t+1)+0.6t)+4+1.2=0


We calculate terms in parentheses: -(2(t+1)+0.6t), so:

2(t+1)+0.6t

We add all the numbers together, and all the variables

0.6t+2(t+1)

We multiply parentheses

0.6t+2t+2

We add all the numbers together, and all the variables

2.6t+2

Back to the equation:

-(2.6t+2)


We add all the numbers together, and all the variables

2t-(2.6t+2)+5.2=0

We get rid of parentheses

2t-2.6t-2+5.2=0

We add all the numbers together, and all the variables

-0.6t+3.2=0

We move all terms containing t to the left, all other terms to the right

-0.6t=-3.2

t=-3.2/-0.6

t=5+0.2/0.6