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2(1.5x+10)=3(x+6)x=
We move all terms to the left:
2(1.5x+10)-(3(x+6)x)=0
We multiply parentheses
2x-(3(x+6)x)+20=0
We calculate terms in parentheses: -(3(x+6)x), so:We get rid of parentheses
3(x+6)x
We multiply parentheses
3x^2+18x
Back to the equation:
-(3x^2+18x)
-3x^2+2x-18x+20=0
We add all the numbers together, and all the variables
-3x^2-16x+20=0
a = -3; b = -16; c = +20;
Δ = b2-4ac
Δ = -162-4·(-3)·20
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{31}}{2*-3}=\frac{16-4\sqrt{31}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{31}}{2*-3}=\frac{16+4\sqrt{31}}{-6} $
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