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2(1/2q+1)=-3(2q-1)
We move all terms to the left:
2(1/2q+1)-(-3(2q-1))=0
Domain of the equation: 2q+1)!=0We multiply parentheses
q∈R
2q-(-3(2q-1))+2=0
We calculate terms in parentheses: -(-3(2q-1)), so:We get rid of parentheses
-3(2q-1)
We multiply parentheses
-6q+3
Back to the equation:
-(-6q+3)
2q+6q-3+2=0
We add all the numbers together, and all the variables
8q-1=0
We move all terms containing q to the left, all other terms to the right
8q=1
q=1/8
q=1/8
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