2(1/2q+1)=-3(2q-1)+10

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Solution for 2(1/2q+1)=-3(2q-1)+10 equation: 



2(1/2q+1)=-3(2q-1)+10

We move all terms to the left:

2(1/2q+1)-(-3(2q-1)+10)=0



Domain of the equation: 2q+1)!=0

q∈R



We multiply parentheses

2q-(-3(2q-1)+10)+2=0



We calculate terms in parentheses: -(-3(2q-1)+10), so:

-3(2q-1)+10

We multiply parentheses

-6q+3+10

We add all the numbers together, and all the variables

-6q+13

Back to the equation:

-(-6q+13)



We get rid of parentheses

2q+6q-13+2=0

We add all the numbers together, and all the variables

8q-11=0

We move all terms containing q to the left, all other terms to the right

8q=11

q=11/8

q=1+3/8

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