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2(1/2q+1)=3(2q-1)4+(2q+1)
We move all terms to the left:
2(1/2q+1)-(3(2q-1)4+(2q+1))=0
Domain of the equation: 2q+1)!=0We multiply parentheses
q∈R
2q-(3(2q-1)4+(2q+1))+2=0
We calculate terms in parentheses: -(3(2q-1)4+(2q+1)), so:We get rid of parentheses
3(2q-1)4+(2q+1)
We multiply parentheses
24q+(2q+1)-12
We get rid of parentheses
24q+2q+1-12
We add all the numbers together, and all the variables
26q-11
Back to the equation:
-(26q-11)
2q-26q+11+2=0
We add all the numbers together, and all the variables
-24q+13=0
We move all terms containing q to the left, all other terms to the right
-24q=-13
q=-13/-24
q=13/24
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