2(1/2q+20)=3(2q-1)+4(2q+1)

Solution for 2(1/2q+20)=3(2q-1)+4(2q+1) equation:

2(1/2q+20)=3(2q-1)+4(2q+1)

We move all terms to the left:

2(1/2q+20)-(3(2q-1)+4(2q+1))=0


Domain of the equation: 2q+20)!=0

q∈R


We multiply parentheses

2q-(3(2q-1)+4(2q+1))+40=0


We calculate terms in parentheses: -(3(2q-1)+4(2q+1)), so:

3(2q-1)+4(2q+1)

We multiply parentheses

6q+8q-3+4

We add all the numbers together, and all the variables

14q+1

Back to the equation:

-(14q+1)


We get rid of parentheses

2q-14q-1+40=0

We add all the numbers together, and all the variables

-12q+39=0

We move all terms containing q to the left, all other terms to the right

-12q=-39

q=-39/-12

q=3+1/4