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2(1/2t+5)=3(2)
We move all terms to the left:
2(1/2t+5)-(3(2))=0
Domain of the equation: 2t+5)!=0determiningTheFunctionDomain 2(1/2t+5)-32=0
t∈R
We multiply parentheses
2t+10-32=0
We add all the numbers together, and all the variables
2t-22=0
We move all terms containing t to the left, all other terms to the right
2t=22
t=22/2
t=11
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